Guinness Book of World Records Attempt:
On Saturday, February 18, 2012, JB PowerSystems will be attempted to set the new world record for the amount of electricity produced by one person using simple machines, which currently is 3.5 kilowatt hours in 24 hours. This attempt took place at Strasburg Park, in Strasburg, Virginia at 4PM. We pushed our bike to produce a total of 3.6 kwh in 2 hrs, where the current Guinness Book world record holder rode their bike for 3.5 kwh in 24 hrs. Consequently, we pushed the bike to beat the world record but will ride the bike at a later date to beat the world record.
Visit http://www.nvdaily.com/lifestyle/2012/02/changing-minds.php to read a recent interview.
EPS Electric Engineering Testing Company did the testing for the event:
1. We have a 3 phase generator that has 42 coils in it. (the more coils reduced the number of rotations it needs to produce energy)
2. We have 18/1 gearbox. (this is called a torque multiplier)
3. We have a toque arm that is 10 feet long.
4. The Force is produced by man pushing.
5. We have a fish scale to pull the torque bar to see what force the man would have to push. (10-25)lbs
6. The Man will turn the torque 5 complete rotations.
7. Each rotation turns the gearbox, which turns the generator 5 x 18=90 rpm
8. Each rotation the man travels 10 ft x 3.14 (360 degrees) = 31.4 feet x 5 rpm = 157 ft travel per minute x 25 lbs(per ft) =3925 ft lbs minute x .74 (watt sec)=2904 watts per minute
9. The engineer meter read 30 volts x 20 amps = 600 watts per phase x 1.732 = 1020 watts per minute.
10. 1020 watts is true power watts out of 1800 watts produced, also 1020 watts per second x 0.74(watt Second) = 754.8 ft-lb's sec x 60 sec(minute) =4 5,288 ft lbs per minute x 0.74 = 33513 ft-lb's per minute and the energy used to produce this is 3925 ft-lb's minute. Take 33513 ft-lb's minute divided by 3925 = 8.5 power. It produce than used
*The engineering company stated that this does not break any laws of physics and this is the most efficient way to produce electricty without pollution.
Visit http://www.nvdaily.com/lifestyle/2012/02/changing-minds.php to read a recent interview.
EPS Electric Engineering Testing Company did the testing for the event:
1. We have a 3 phase generator that has 42 coils in it. (the more coils reduced the number of rotations it needs to produce energy)
2. We have 18/1 gearbox. (this is called a torque multiplier)
3. We have a toque arm that is 10 feet long.
4. The Force is produced by man pushing.
5. We have a fish scale to pull the torque bar to see what force the man would have to push. (10-25)lbs
6. The Man will turn the torque 5 complete rotations.
7. Each rotation turns the gearbox, which turns the generator 5 x 18=90 rpm
8. Each rotation the man travels 10 ft x 3.14 (360 degrees) = 31.4 feet x 5 rpm = 157 ft travel per minute x 25 lbs(per ft) =3925 ft lbs minute x .74 (watt sec)=2904 watts per minute
9. The engineer meter read 30 volts x 20 amps = 600 watts per phase x 1.732 = 1020 watts per minute.
10. 1020 watts is true power watts out of 1800 watts produced, also 1020 watts per second x 0.74(watt Second) = 754.8 ft-lb's sec x 60 sec(minute) =4 5,288 ft lbs per minute x 0.74 = 33513 ft-lb's per minute and the energy used to produce this is 3925 ft-lb's minute. Take 33513 ft-lb's minute divided by 3925 = 8.5 power. It produce than used
*The engineering company stated that this does not break any laws of physics and this is the most efficient way to produce electricty without pollution.
Objective:
JB PowerSystems is an environmentally friendly, renewable energy company introducing a revolutionary energy idea to the market. This is just the beginning of one of many projects that the company has in development. This is designed to be retrofitted for multiple platforms including, but not limited to wind, water, mechanical, and battery powered systems.
How It Works:
The Mechanics of how Torque, Force, and a gearbox all work together to multiply energy. Read about the Energy Multiplier System.
Reverse Engineering (How I Prove My Theory Works)
Let's take a 7 million watt(mw) generator and reverse engineer it to show how much force we need to push it by my theory. Take
7,000,000 watts and multiply it by .74ftlbs/second. This comes to 5,180,000 ftlbs. This number is then multiplied by 60 (seconds in a minute), which then comes to 31,080,000ftlbs/minute. A gearbox (torque multiplier) rotates 18 times/minute. Divide 31,080,000 by 18 and get 1,726,666.7ftlbs/rotation. The torque is 300 ft long, 300 into 1,726,666.7 is 5755.5ftlbs of force. To find the force of the horse power of the electric locomotive, take 5755.5ftlbs into 33,000ftlbs(hp minute) and it comes to .18 hp. The track for the locomotive is 300ft x 3.14 = 951ft in circumference. You then divide 951 by 60ft (1 minute)=15.8. This number shows how many 60 feet sections it takes to complete the circle. To find the horse power, one must take 15.8 and mutiply that by .18. This gives us 2.84 horse power. Then you take 2.84hp for 1 minute amd multiply it by 60 minutes (because there are 60 minutes in one hour) and that equals 170.64 hp for one hour. Next take the 170.84 hp x 746 watts =127,298 watts for an hour to produce 7,000,000 watts per hr (this is 7,000 kilowatt hours). By taking 7,000,000 watts and dividing that by 127,298 watts, this produces a ratio of 55 to 1. If we have the average friction loss of 20%, we would take .80 (1.0 minus .2) and multiply that by 55 to get a ratio of 44 to 1.
7,000,000 watts and multiply it by .74ftlbs/second. This comes to 5,180,000 ftlbs. This number is then multiplied by 60 (seconds in a minute), which then comes to 31,080,000ftlbs/minute. A gearbox (torque multiplier) rotates 18 times/minute. Divide 31,080,000 by 18 and get 1,726,666.7ftlbs/rotation. The torque is 300 ft long, 300 into 1,726,666.7 is 5755.5ftlbs of force. To find the force of the horse power of the electric locomotive, take 5755.5ftlbs into 33,000ftlbs(hp minute) and it comes to .18 hp. The track for the locomotive is 300ft x 3.14 = 951ft in circumference. You then divide 951 by 60ft (1 minute)=15.8. This number shows how many 60 feet sections it takes to complete the circle. To find the horse power, one must take 15.8 and mutiply that by .18. This gives us 2.84 horse power. Then you take 2.84hp for 1 minute amd multiply it by 60 minutes (because there are 60 minutes in one hour) and that equals 170.64 hp for one hour. Next take the 170.84 hp x 746 watts =127,298 watts for an hour to produce 7,000,000 watts per hr (this is 7,000 kilowatt hours). By taking 7,000,000 watts and dividing that by 127,298 watts, this produces a ratio of 55 to 1. If we have the average friction loss of 20%, we would take .80 (1.0 minus .2) and multiply that by 55 to get a ratio of 44 to 1.
Power System Design
The electric locomotive in the bottom of the picture will be traveling on a circular track like demonstrated. The electric locomotive is connected to the torque (blades) inside the center of the track. When the electric locomotive begins moving, it then turns the blades along with it. The torque (blades) are connected to a gear box, which is then connected to a generator, which will then generate electricity. One important feature that makes the PowerSystem distinctive is that it is almost entirely pollution free. Using the electric locomotive the PowerSystem can be located close to a city and it will not create any pollution other than noise pollution. This noise pollution can be masked by how the PowerSystem is housed, either in a block building structure or even underground.
JB PowerSystems Wind Mill Conversion:
This is the world’s largest wind turbine the Enercon E-126. This turbine has a rotor diameter of 413 feet (126m). This new turbine is officially rated at 6 megawatts, but will most likely produce 7+ megawatts (or 20 million kilowatt hours per year). In the US that would be about, 938 kwh per home per month, 12 months, that’s 11,256 kwh per year per house. That’s 1,776 American homes on one wind turbine. That’s enough to power about 5,000 households of four in Europe. The E-126 has no gearbox attaching the turbine blades to the generator, in fact, the generator is housed just at the widest part of the nose cone, it takes up the entire width of the nacelle to generate power more efficiently, and provide longer service life with less wear. The generator and blades would be incorporated into our PowerSystem above. By attaching a gearbox to this wind mill and incorporating it into our PowerSystem the gearbox will be able to reduce the number revolutions the blades will have to rotate and it will produce the same amount of power. Furthermore, when incorporating the wind mill into our PowerSystem, we are only using the blades and the generator, we are not using the long tower supporting the blades. When the wind mill is part of our Power System it will lay flat and parallel to the ground.
Formula 1:
This formula demonstrates the force of the electric locomotive. Once it has overcome the force of inertia as well as friction, the electric locomotive can move 13,000 tons, 12 miles, in 1 hour. In this 1 hour of time, the electric locomotive only uses approximately 51.00 kWH. When you take the force of a electric locomotive at a distance of 200 ft. out and attach a 24:1 gear box on the generator, the locomotive only has to move 1/2 revolution per minute to make 7,540 watts. When you take the 7,540 kw or 7,580,000 mega watts produced divided by 12 rpm it equals = 631,667 watts per revolution. Divided by the 200 ft blade distance and it equals = 3,158 foot lbs of force per second that is needed.
Formula 2:
This formula demonstrates the energy cost of 0.1355 kWh, to move 100lbs, 3600ft. The picture of the power system below demonstrates how the train will travel around the circumference of the circle six times or approximately 3600ft. pushing the blades which will turn the generator to produce the electricity. Combining Formula 3 with Formula 2, it explains how much horsepower the power system below can produce. Another aspect to understand is that depending upon the generator and gearbox used with the PowerSystem, it may only take a quarter turn of the electric locomotive to produced energy. A gearbox provides speed and torque conversions from a rotating power source to another device using gear ratios. Most modern gearboxes are used to increase torque while reducing the speed of a prime mover output shaft. This means that the output shaft of a gearbox will produce a mechanical advantage, causing an increase in torque. So using one of these specific gearboxes, it does not need to make several revolutions to start to generate power. But, the more revolutions or farther the electric locomotive travels the more energy it will generate.
Formula 4:
These formulas are used to determine both the Total Output of each generator (7.2mW) as well as the total amount of Force that the electric locomotive needs in order to create said energy. As stated in the formulas above, the electric locomotive needs only 51kWh in order to move 13000 tons. Using this formula, you can see that the electric locomotive only needs 88,000 ft. lbs (which is equal to 44 tons) to create 7.2mW. The electric locomotive clearly exceeds these minimal requirements.